实数计算题(凑十法计算题)

更新:2024-04-27 11:09:05  分享:wangsihai

本篇文章给大家谈谈实数计算题,以及凑十法计算题对应的知识点,希望对各位有所帮助,不要忘了收藏本站喔。

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初中数学实数计算题:已知a,b,c为实数,且ab/(a+b)=1/3,bc/(b+c)=1/4,ac/(a+c)=1/5,求abc/(ab+bc+ac)的值

已知的分别倒数后1/a+1/b=3 1/b+1/c=4 1/a+1/c=5

三式相加除以2得:1/a+1/b+1/c=6

abc/(ab+bc+ac)=1/(1/c+1/b+1/a)=1/6

√80-√45实数计算题怎么算?你是怎么得出结果的?

根号80=4根号5

根号45=3根号5

√80-√45=根号(16×5)-根号(9×5)=4根号5-3根号5=根号5

求初二数学60道计算题、30道实数运算题、30道解方程组(带解)

(1)99²-2.99²

(2)80×3.5²+160×3.5×1.5+80×1.5²

(3)181²-61²÷301²-181²

(4)5x-5y+5z

(5)-5a²+25a-5a

(6)2a(b+c)-3(b+c)

(7)(ab+a)+(b+1)

(8)-4m³+16m³-28m

(9)16x-25x³y²

(10)36m²a-9m²a²-36m²

√32-3√1/2+√2

√12+√27/√3-√1/3×√12

√50+√30/√8-4

(√6-2√15)×√3-6√1/2

√2/3-4√216+43√1/6

√8+√30-√2

√40-5√1/10+√10

√2+√8/√2

√2/9+√50+√32

(1-√3)(√3+2)

(√8+3√6)÷√2-√3×√0.7

(-3+√6)(-3-√6)-(√3-1/√3)²

³√0.125-√3

1/16+³√(1-7/8)²

√2/3-√216+42√1/6

解方程√3

X-1=√2

X

求X

{√5

X-3√

Y=1}

{√3

X-√5

Y=2}

注:X全部不在根号内

√(1/2x)^2+10/9x^2

=√[1/(4x^2)+10/(9x^2)]

=√49/36x^2

若x0,=7/(6x)

若x0,=-7/(6x)

√a^4mb^2n+1

=√(a^2mb^n)^2+1

=a^2mb^n+1

√(4a^5+8a^4)(a^2+3a+2)

=√[4a^4(a+2)][(a+2)(a+1)]

=√[4a^4(a+2)^2(a+1)]

=2a^2(a+2)√(a+1)

.

3√(1/6)-4√(50)+30√(2/3)

答案3√(1/6)-4√(50)+30√(2/3)

=

3×√6/6-4×5√2+30×√6/3

=√6/2-20√2+10√6

2.

(1-根号2)/2乘以(1+根号2)/2

题是这样的二分之一减根号2乘以二分之一加根号2

答案:(1-根号2)/2乘以(1+根号2)/2

=(1-√2)*(1-√2)/4

=(1-2)/4

=-1/4

1.3√(1/6)-4√(50)+30√(2/3)

答案3√(1/6)-4√(50)+30√(2/3)

=

3×√6/6-4×5√2+30×√6/3

=√6/2-20√2+10√6

2.

(1-根号2)/2乘以(1+根号2)/2

题是这样的二分之一减根号2乘以二分之一加根号2

答案:(1-根号2)/2乘以(1+根号2)/2

=(1-√2)*(1-√2)/4

=(1-2)/4

=-1/4

3.√(1/2x)^2+10/9x^2

√[(1/2x)^2+10/9x^2]

=√(x^2/4+10x^2/9)

=√(9x^2/36+40x^2/36)

=√(49x^2/36)

=7x/6;

4.√a^4mb^2n+1(a、b为正数)

[√(a^4mb^2n)]+1(a、b为正数)

=a^2mb^n+1;

5.√(4a^5+8a^4)(a^2+3a+2)(a=0)

√[(4a^5+8a^4)(a^2+3a+2)](a=0)

=√[4a^4(a+2)(a+2)(a+1)]

=√[(2a^2)^2(a+2)^2(a+1)]

=2a^2(a+2)√(a+1).

太多了呀,只能这样了,我还有事

您好!

①5√8-2√32+√50

=5*3√2-2*4√2+5√2

=√2(15-8+5)

=12√2

②√6-√3/2-√2/3

=√6-√6/2-√6/3

=√6/6

③(√45+√27)-(√4/3+√125)

=(3√5+3√3)-(2√3/3+5√5)

=-2√5+7√5/3

④(√4a-√50b)-2(√b/2+√9a)

=(2√a-5√2b)-2(√2b/2+3√a)

=-4√a-6√2b

⑤√4x*(√3x/2-√x/6)

=2√x(√6x/2-√6x/6)

=2√x*(√6x/3)

=2/3*x*√6

⑥(x√y-y√x)÷√xy

=x√y÷√xy-y√x÷√xy

=√x-√y

⑦(3√7+2√3)(2√3-3√7)

=(2√3)^2-(3√7)^2

=12-63

=-51

⑧(√32-3√3)(4√2+√27)

=(4√2-3√3)(4√2+3√3)

=(4√2)^2-(3√3)^2

=32-27

=5

⑨(3√6-√4)²

=(3√6)^2-2*3√6*√4+(√4)^2

=54-12√6+4

=58-12√6

⑩(1+√2-√3)(1-√2+√3)

=[1+(√2-√3)][1-(√2-√3)]

=1-(√2-√3)^2

=1-(2+3+2√6)

=-4-2√6

1.

=5√5

-

1/25√5

-

4/5√5

=√5*(5-1/25-4/5)

=24/5√5

2.=√144+576

=√720

=12√5

3.)√(8/13)^2-(2/13)^2

=

√(8/13+2/13)(8/13-2/13)

=(2/13)√15

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